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The Constructible universe (denoted $L$) was invented by Kurt Gödel as a transitive inner model of $\text{ZFC+}$$\text{GCH}$ (assuming the consistency of $\text{ZFC}$) showing that $\text{ZFC}$ cannot disprove $\text{GCH}$. It was then shown to be an important model of $\text{ZFC}$ for its satisfying of other axioms, thus making them consistent with $\text{ZFC}$. The idea is that $L$ is built up by ranks like $V$. $L_0$ is the empty set, and $L_{\alpha+1}$ is the set of all easily definable subsets of $L_\alpha$. The assumption that $V=L$ (also known as the Axiom of constructibility) is undecidable from $\text{ZFC}$, and implies many axioms which are consistent with $\text{ZFC}$. A set $X$ is constructible iff $X\in L$. $V=L$ iff every set is constructible.
$\mathrm{def}(X)$ is the set of all “easily definable” subsets of $X$ (specifically the $\Delta_0$ definable subsets). More specifically, a subset $x$ of $X$ is in $\mathrm{def}(X)$ iff there is a first-order formula $\varphi$ and $v_0,v_1…v_n\in X$ such that $x=\{y\in X:\varphi^X[y,v_0,v_1…v_n]\}$. Then, $L_\alpha$ and $L$ are defined as follows:
$L_\alpha(W)$ for a class $W$ is defined the same way except $L_0(W)=\text{TC}(\{W\})$ (the transitive closure of $\{W\}$). $L_\alpha[W]$ for a class $W$ is defined in the same way as $L$ except using $\mathrm{def}_W(X)$, where $\mathrm{def}_W(X)$ is the set of all $x\subseteq X$ such that there is a first-order formula $\varphi$ and $v_0,v_1…v_n\in X$ such that $x=\{y\in X:\varphi^X[y,W,v_0,v_1…v_n]\}$ (because the relativization of $\varphi$ to $X$ is used and $\langle X,\in\rangle$ is not used, this definition makes sense even when $W$ is not in $X$).
$L[W]=\bigcup_{\alpha\in\mathrm{Ord}}L_\alpha[W]$ is always a model of $\text{ZFC}$, and always satisfies $\text{GCH}$ past a certain cardinality. $L(W)=\bigcup_{\alpha\in\mathrm{Ord}}L_\alpha(W)$ is always a model of $\text{ZF}$ but need not satisfy $\text{AC}$ (the axiom of choice). In particular, $L(\mathbb{R})$ is, under large cardinal assumptions, a model of the axiom of determinacy. However, Shelah proved that if $\lambda$ is a strong limit cardinal of uncountable cofinality then $L(\mathcal{P}(\lambda))$ is a model of $\text{AC}$.
For $\alpha\leq\omega$, $L_\alpha=V_\alpha$. However, $|L_{\omega+\alpha}|=\aleph_0 + |\alpha|$ whilst $|V_{\omega+\alpha}|=\beth_\alpha$. Unless $\alpha$ is a $\beth$-fixed point, $|L_{\omega+\alpha}|<|V_{\omega+\alpha}|$. Although $L_\alpha$ is quite small compared to $V_\alpha$, $L$ is a tall model, meaning $L$ contains every ordinal. In fact, $V_\alpha\cap\mathrm{Ord}=L_\alpha\cap\mathrm{Ord}=\alpha$, so the ordinals in $V_\alpha$ are precisely those in $L_\alpha$.
If $0^{\#}$ exists (see below), then every uncountable cardinal $\kappa$ has $L\models$”$\kappa$is totally ineffable (and therefore the smallest actually totally ineffable cardinal $\lambda$ has many more large cardinal properties in $L$).
However, if $\kappa$ is inaccessible and $V=L$, then $V_\kappa=L_\kappa$. Furthermore, $V_\kappa\models (V=L)$. In the case where $V\neq L$, it is still true that $V_\kappa^L=L_\kappa$, although $V_\kappa^L$ will not be $V_\kappa$. In fact, $\mathcal{P}(\omega)\not\in V_\kappa^L$ if $0^{\#}$ exists.
Here is a list of statements true in $L$ of any model of $\text{ZF}$:
Main article: axiom of determinacy
When using second order logic in the definition of $\mathrm{def}$, the new hierarchy is called $L_\alpha^{II}$. Interestingly, $L^{II}=\text{HOD}$. When using $\mathcal{L}_{\kappa,\kappa}$, the hierarchy is called $L_\alpha^{\mathcal{L}_{\kappa,\kappa}}$, and $L\subseteq L^{\mathcal{L}_{\kappa,\kappa}}\subseteq L(V_\kappa)$. Finally, when using $\mathcal{L}_{\infty,\infty}$, it turns out that the result is $V$.
Chang’s Model is $L^{\mathcal{L}_{\omega_1,\omega_1}}$. Chang proved that $L^{\mathcal{L}_{\kappa,\kappa}}$ is the smallest inner model of $\text{ZFC}$ closed under sequences of length $<\kappa$.
To be expanded.
A cardinal $κ$ is Silver if in a set-forcing extension there is a club in $κ$ of generating indiscernibles for $V_κ$ of order-type $κ$. This is a very strong property downwards absolute to $L$, e.g.:(Gitman & Shindler, n.d.)
$0^{\#}$ (zero sharp) is a $\Sigma_3^1$ real number which, under the existence of many Silver indiscernibles (a statement independent of $\text{ZFC}$), has a certain number of properties that contredicts the axiom of constructibility and implies that, in short, $L$ and $V$ are “very different”. Technically, under the standard definition of $0^\#$ as a (real number encoding a) set of formulas, $0^\#$ provably exists in $\text{ZFC}$, but lacks all its important properties. Thus the expression “$0^\#$ exists” is to be understood as “$0^\#$ exists and there are uncountably many Silver indiscernibles”.
Assume there is an uncountable set of Silver indiscernibles. Then $0^{\#}$ is defined as the set of all Gödel numberings of first-order formula $\varphi$ such that $L_{\aleph_{\omega}}\models\varphi(\aleph_0,\aleph_1…\aleph_n)$ for some $n$.
“$0^{\#}$ exists” is used as a shorthand for “there is an uncountable set of Silver indiscernibles”; since $L_{\aleph_\omega}$ is a set, $\text{ZFC}$ can define a truth predicate for it, and so the existence of $0^{\#}$ as a mere set of formulas would be trivial. It is interesting only when there are many (in fact proper class many) Silver indiscernibles. Similarly, we say that “$0^{\#}$ does not exist” if there are no Silver indiscernibles.
If $0^♯$ exists then:
then $D_{δ,n}$ is a definable dense subclass of $\mathbb{P}$ in $L$.
The following statements are equivalent:
The existence of $0^♯$ is implied by:
Note that if $0^♯$ exists then for every Silver indiscernible (in particular for every uncountable cardinal) there is a nontrivial elementary embedding $j:L\rightarrow L$ with that indiscernible as its critical point. Thus if any such embedding exists, then a proper class of those embeddings exists.
An EM blueprint (Ehrenfeucht-Mostowski blueprint) $T$ is any theory of the form $\{\varphi:(L_\delta;\in,\alpha_0,\alpha_1…)\models\varphi\}$ for some ordinal $\delta>\omega$ and $\alpha_0<\alpha_1<\alpha_2…$ are indiscernible in the structure $L_\delta$. Roughly speaking, it’s the set of all true statements about $\alpha_0,\alpha_1,\alpha_2…$ in $L_\delta$.
For an EM blueprint $T=\{\varphi:(L_\delta;\in,\alpha_0,\alpha_1…)\models\varphi\}$, the theory $T^{-}$ is defined as $\{\varphi:L_\delta\models\varphi\}$ (the set of truths about any definable elements of $L_\delta$). Then, the structure $\mathcal{M}(T,\alpha)=(M(T,\alpha);E)\models T^{-}$ has a very technical definition, but it is indeed uniquely (up to isomorphism) the only structure which satisfies the existence of a set $X$ of $\mathcal{M}(T,\alpha)$-ordinals such that:
$0^\#$ is then defined as the unique EM blueprint $T$ such that:
If the EM blueprint meets 1. then it is called well-founded. If it meets 2. and 3. then it is called remarkable.
If $0^\#$ exists (i.e. there is a well-founded remarkable EM blueprint) then it happens to be equivalent to the set of all $\varphi$ such that $L\models\varphi[\kappa_0,\kappa_1…]$ for some uncountable cardinals $\kappa_0,\kappa_1…<\aleph_\omega$. This is because the associated $M(T,\alpha)$ will always have $M(T,\alpha)\prec L$ and furthermore $\kappa_0,\kappa_1…$ would be indiscernibles for $L$.
$0^\#$ exists interestingly iff some $L_\delta$ has an uncountable set of indiscernables. If $0^\#$ exists, then there is some uncountable $\delta$ such that $M(0^\#,\omega_1)=L_\delta$ and $L_\delta$ therefore has an uncountable set of indiscernables. On the other hand, if some $L_\delta$ has an uncountable set of indiscernables, then the EM blueprint of $L_\delta$ is $0^\#$.
$0^\dagger$ (zero dagger) is a set of integers analogous to $0^\sharp$ and connected with inner models of measurability.(Kanamori & Awerbuch-Friedlander, 1990)
$0^{sword}$ is connected with nontrivial Mitchell rank. $¬ 0 ^{sword}$ (not zero sword) means that there is no mouse with a measure of Mitchell order $> 0$.(Sharpe & Welch, 2011)
$0^\P$ (zero pistol) is connected with strong cardinals. $¬ 0^\P$ (not zero pistol) means that a core model may be built with a strong cardinal, but that there is no class of indiscernibles for it that is closed and unbounded in $\mathrm{Ord}$).(Sharpe & Welch, 2011) $0^¶$ is “the sharp for a strong cardinal”, meaning the minimal sound active mouse $\mathcal{M}$ with $M | \mathrm{crit}(\dot F^{\mathcal{M}}) \models \text{“There exists a strong cardinaly”}$, with $\dot F^{\mathcal{M}}$ being the top extender of $\mathcal{M}$.(Nielsen & Welch, 2018)